# 48÷2(9+3)=?

**URL:** https://forums.speedlife.net/t/48-2-9-3/257862
**Category:** Shift518 Off Topic
**Created:** [April 12, 2011, 9:21pm UTC](https://forums.speedlife.net/t/48-2-9-3/257862 "2011-04-12T21:21:40Z")
**Posts on this page:** 1
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### Author: ![Vovchandr](https://yyz2.discourse-cdn.com/flex034/user_avatar/forums.speedlife.net/vovchandr/32/6275_2.png) [@Vovchandr](https://forums.speedlife.net/u/Vovchandr)
#### Post date: [April 13, 2011, 6:00pm UTC](https://forums.speedlife.net/t/48-2-9-3/257862/163 "2011-04-13T18:00:28Z")

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> [@\*\*\*\*Official: Southgate Meet Thread\*\*\*\*](https://forums.speedlife.net/t/official-southgate-meet-thread/29171/1481):
>
> maybe its the russian in you, but, its called ORDER of operations.  
> not my name is vlad and i do math however i fee like it operations.
> 
> Parenthesis  
> Exponents  
> Multiplication & Division FROM LEFT TO RIGHT  
> Addition and Subtraction FROM LEFT TO RIGHT
> 
> how the fuck do you get 18 + 6 if you are supposed to do whats inside the parenthesis first???  
> you do NOT distribute the 2 at all.  
> holy shit, its like highschool again, where i had to always explain everything the teacher taught because the kids in my class were all tards:retardclap

Because that’s how it works.

It’s NOT THE SAME as having a multiplication sign between them

His could also be written as

48/6(3+1)

I’ll quote this again, as you dont get it

> Distributive property of multiplication. Early Algebra.

> The distributive property of multiplication CLEARLY states that the 2(9+3) is an entire term and CANNOT be broken up. 2(9+3) follows the distributive property which can be rewritten as (2_9+2_3). Let me repeat the 2 outside of the parenthesis follows the distributive property of multiplication and must be factored and simplified before performing any other operations on it.

> So this can be rewritten as:  
> 48 / (2_9 + 2_3)

> Which leaves us with

> 48 / 24 = 2

> Answer = 2.

> Lastly for those using Google or any other online calculator. These do not understand many theorems or properties so you must explicitly explain what you mean. There is a difference between 48 / 2 _(9+3) and 48 / 2(9+3). The first notation reads 48 / 2 \* 1(9+3) while the second reads 48 / (2_9+2\*3). Be very careful with your signs.

Ill also copy this from math.edu

Link works Better than quote

[http://www.math.unt.edu/mathlab/emathlab/distributive\_property\_of\_multipl.htm](http://www.math.unt.edu/mathlab/emathlab/distributive_property_of_multipl.htm)

> -

> The distributive property of multiplication over addition is simply this:\* it makes no difference whether you add two or more terms together first, and then multiply the results by a factor, or whether you multiply each term alone by the factor first, and then add up the results.

> That is,

> \*\*\* adding up the term first; then multiplying by the factor\*\* =\* multiplying each term by the factor first, then adding up the resulting terms

> -

> That is:\*\*\*\*\*\* Factor(Term1 + Term2 + … + TermN)\* =\*\* Factor(Term1) + Factor(Term2) + … + Factor(TermN)

> If we call the Factor “a,”\* and we call the terms “b”, “c,”…“t”, then this statement begins to look like a mathematical statement:

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* a(b + c + … + t)\*\*\* = a(b) + a(c) + … +a(t)

> -

> \*\* EXAMPLE:\*\*\* (The factor is 3, and the three terms\* are 2, 7, -5)

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* 3(2 + 7 - 5)\* =\*\* 3(2) + 3(7) + (3)(-5)

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* 3(4) \*\*\*\*\*\*\* =\*\*\*\* 6\*\*\* +\* 21\*\*\* -\* 15

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* 12\*\*\*\*\*\*\*\* =\*\* 12

> -

> -

> This is kinda cool, but you might wonder\* what possible use it might be.\* I mean, really, why wouldn’t you ALWAYS add the terms together first, and avoid all that yukky multiplication?\*\* Well, the answer is:\*\* It comes in very useful when you have terms that cannot be added together first, because they are not like terms.

> Case in point:\*\*\* 3(2x + 4).\*\*\* We can’t combine the 2x and the 4, because the first is x’s and the second is 1’s (four of them).\* But, suppose this expression showed up in an equation like:

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* 3(2x + 4) = 5

> and we were asked to solve for x?\* What to do?\* We have to get the x’s untied from the 1’s, right?\* Using the distributive property of multiplication over addition is what is going to let us solve this equation:

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* 3(2x) + 3(4) = 5\*\*\*\*\*\* Ta-da!\*\* Now the x’s are unhooked from the 1’s

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* 6x + 12\*\* =\* 5

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* 6x =\* 5 - 12

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* =\* -7

> \*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\*\* x\* =\* -7/6

> -

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