# Does .999999 = 1 vPOLL **URL:** \ **Category:** NYSpeed Off Topic\ **Created:** [June 20, 2006, 8:06am UTC](https://forums.speedlife.net/t/does-999999-1-vpoll/13546 "2006-06-20T08:06:47Z")\ **Posts on this page:** 1\ **Showing post:** 129
**Author:** ![Ninja](https://avatars.discourse-cdn.com/v4/letter/n/53a042/32.png) [@Ninja](https://forums.speedlife.net/u/Ninja)\ **Post date:** [December 8, 2006, 9:52am UTC](https://forums.speedlife.net/t/does-999999-1-vpoll/13546/129 "2006-12-08T09:52:05Z")
> [@BikerFry](#): > > That is where the “trick” or, as I like to call it, the mathematical error lies. That equation was not solved correctly. That equation cannot be solved for a real number. > > 9.99~ and .99~ both have decimal places that go on for infinity. They are not real numbers. 9.99~ - .99~ is not = 9. It is equal to a number infinitely close to 9, but it is not a real number. > > So while this is a cute trick of algebra, it is based on one false assumption: That you can solve infinity - infinity and get a real number. You cannot, as infinity is not a real number. > > [http://mathforum.org/library/drmath/view/57069.html](http://mathforum.org/library/drmath/view/57069.html) > [http://www.galactic-guide.com/articles/8R69.html](http://www.galactic-guide.com/articles/8R69.html) :word: this is what I was trying to come out with but I had to go back to work… Solving the above equation the way they do it like saying infinity - infinity = zero… can’t do it. Also… just because x = .99999999999 in the two equations you are subtracting… doesn’t mean you can just plug it in to the 9x = 9 equation… Because guess what 9x = 9 … equates to x = 1… Using the logic of whoever is trying to prove .9999999 = 1, I can plug any number I want into x… 897498275 = 1… Just cause I prove x = .99999999 in equation #1 … doesn’t mean wherever x is I can imediatly plug in .99999999 --- _[View the full topic](https://forums.speedlife.net/t/does-999999-1-vpoll/13546)._