# Fun with Integral Calculus, or I'm totally not getting laid.

**URL:** <https://forums.speedlife.net/t/fun-with-integral-calculus-or-im-totally-not-getting-laid/241653>\
**Category:** Shift518 Automotive\
**Created:** [January 28, 2009, 5:22pm UTC](https://forums.speedlife.net/t/fun-with-integral-calculus-or-im-totally-not-getting-laid/241653 "2009-01-28T17:22:31Z")\
**Posts on this page:** 1\
**Showing post:** 13

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**Author:** ![1320-20V](https://yyz2.discourse-cdn.com/flex034/user_avatar/forums.speedlife.net/1320-20v/32/6474_2.png) [@1320-20V](https://forums.speedlife.net/u/1320-20V)\
**Post date:** [January 28, 2009, 6:45pm UTC](https://forums.speedlife.net/t/fun-with-integral-calculus-or-im-totally-not-getting-laid/241653/13 "2009-01-28T18:45:52Z")

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> [@TW or WTT: 2000 LS Integra](https://forums.speedlife.net/t/tw-or-wtt-2000-ls-integra/13233/3):
>
> I’ll join in on this shit.
> 
> pretty sure u-substitution is used for integrals not derivatives. At least I think so.
> 
> Well your y’ should be:  
> y’ = 2(X^2 +1)^(1/2) + (2X^2)(X^2 +1)^(-1/2)

Almost!

y’= 2[(x^2+1)^1/2]+[(2x^2)/(x^2+1)^ **1/2**]

Your second “radical” should not be negative.

Did you just do that out on paper? Did you use the chain rule alone with no U-sub?

Feel free to move out here and be my full time Calc tutor! I have an extra room! LOL

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