# Physics Question **URL:** https://forums.speedlife.net/t/physics-question/102635 **Category:** SON240sx Automotive **Created:** [December 22, 2006, 7:23am UTC](https://forums.speedlife.net/t/physics-question/102635 "2006-12-22T07:23:38Z") **Posts on this page:** 1 **Showing post:** 67
### Author: ![TM1](https://yyz2.discourse-cdn.com/flex034/user_avatar/forums.speedlife.net/tm1/32/5517_2.png) [@TM1](https://forums.speedlife.net/u/TM1) #### Post date: [December 22, 2006, 12:22pm UTC](https://forums.speedlife.net/t/physics-question/102635/67 "2006-12-22T12:22:01Z")
> [@Any good bait stores around](https://forums.speedlife.net/t/any-good-bait-stores-around/10219/42): > > ok…here we go again… > > This is where you are taking on the rest… > > People are saying that because the speed of the converyor matches the speed of the plane, that the plane remains stationary with no air speed across the wing. > > THE SPEED OF THE CONVEYOR HAS NO BEARING ON THE SPEED OF THE PLANE…DUE TO THE VERY FACT THE WHEELS OF THE PLANE HAVE NOTHING TO DO WITH THE ULTIMATE MOVEMENT OF THE PLANE. > > You’re saying the plane will generate airspeed across the wing because of thrust exceeding the conveyor speed. > > Right? > > THE PLANE WILL GENERATE AIRSPEED ACROSS THE WING…DUE TO THE FACT IT WILL BE MOVING THROUGH THE AIR RELATIVE TO THE GROUND…AND EVENTUALLY WILL JUST TAKE OFF FROM THE CONVEYOR SOME DISTANCE DOWN IT… > > i would surmize it would be the exact same take off distance it normally would have…in relation to a static ground object…slightly more taking into account any extra drag from the wheels due to this conveyor spinning them Adam, A planes wheels will not leave the ground until it reachs a certain velocity… I understand what you are saying about the wheels, but you have to understand, as the plane progressively accelerates, so does the conveyor speed. Which means the plane remains still because it will have no forward movement due to the conveyor matching its speed. The only way the plane will take off is if it doubles the speed of the conveyor. A plan needs a runway to take off, which means that the wheels are in contact with the ground until it generates enough thrust from forward movement… Well if the conveyor constantly matches it’s speed from the beginning, the plan will never have a chance to achieve the forward movement needed to generate lift… The wheels are still part of the equation until the force of lift exceeds the force of gravity. 🙂 That’s the only way I can explain it amigo… --- _[View the full topic](https://forums.speedlife.net/t/physics-question/102635)._