# Post a PIC of your latest purchase.

**URL:** <https://forums.speedlife.net/t/post-a-pic-of-your-latest-purchase/235672>\
**Category:** Shift518 Off Topic\
**Created:** [February 14, 2008, 1:56pm UTC](https://forums.speedlife.net/t/post-a-pic-of-your-latest-purchase/235672 "2008-02-14T13:56:25Z")\
**Posts on this page:** 1\
**Showing post:** 18689

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**Author:** ![deadbeatrec](https://yyz2.discourse-cdn.com/flex034/user_avatar/forums.speedlife.net/deadbeatrec/32/6401_2.png) [@deadbeatrec](https://forums.speedlife.net/u/deadbeatrec)\
**Post date:** [August 30, 2013, 7:39am UTC](https://forums.speedlife.net/t/post-a-pic-of-your-latest-purchase/235672/18689 "2013-08-30T07:39:56Z")

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> [@Reformat?](https://forums.speedlife.net/t/reformat/53355/8):
>
> HP = (TQ x RPM) / 5252
> 
> TQ = (HP x 5252) / RPM
> 
> If TQ = 428 @ 4869, then HP = (428 x 4869) / 5252 = 397
> 
> TQ = (397 x 5252) / 4869 = 428
> 
> But wait, that’s what the Accessport shows?!?! That’s because that little device is calculating the numbers exactly how they should be and giving the RPMs where their calculations would be correct. Therefore, it’s all a ‘guess’ really. If you throw the car on a dyno, the numbers, specifically RPM will be drastically diffferent.
> 
> In a real world situation, both can not be peaking at the same RPM. They always cross (read: match) at 5,252 RPM.
> 
> I’d show a mock dyno chart to show you how it’d look, but since I’m working and don’t really know how to do so, it’s a bit impossible.

what if peak HP and TQ were both at 5252??? then it would be exactly the same. i think its possible.

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