Does .999999 = 1 vPOLL

[Ninja]

@BikerFry

That is where the “trick” or, as I like to call it, the mathematical error lies. That equation was not solved correctly. That equation cannot be solved for a real number.

9.99~ and .99~ both have decimal places that go on for infinity. They are not real numbers. 9.99~ - .99~ is not = 9. It is equal to a number infinitely close to 9, but it is not a real number.

So while this is a cute trick of algebra, it is based on one false assumption: That you can solve infinity - infinity and get a real number. You cannot, as infinity is not a real number.

http://mathforum.org/library/drmath/view/57069.html
http://www.galactic-guide.com/articles/8R69.html

:word:

this is what I was trying to come out with but I had to go back to work…

Solving the above equation the way they do it like saying infinity - infinity = zero…

can’t do it.

Also… just because x = .99999999999 in the two equations you are subtracting… doesn’t mean you can just plug it in to the 9x = 9 equation…

Because guess what 9x = 9 … equates to x = 1…

Using the logic of whoever is trying to prove .9999999 = 1, I can plug any number I want into x… 897498275 = 1…

Just cause I prove x = .99999999 in equation #1 … doesn’t mean wherever x is I can imediatly plug in .99999999