And you have this Henderson-Hasselback equation.
and it’s such that
10 = 10.329 + log [ (.0249 - x)/x ]
How do you proceed?
start with:
-0.329=log[(.0249-x)/x]
umm, searches memory…
10^(-0.239)=(.0249-x)/x
I’m not sure if that works.
I’m actually not sure thanks to math A/B. Way to ruin a perfectly fine math system, Regents.
Oh that does work. Thanks to you, sir.
No thanks to CHE214. Bha. What a horrid class.