I’m too rusty to remember how to do simple force equations at the moment and don’t feel like diggin out my Statics book right now.
Anyone want to give this a go for me?
AB = 6 inches
BC = 19 inches
AD = 40 inches
Weight of AD = 40 lbs.
I need to know the Force of Vector BC to support AD.
EDIT: Angle A is 50 degrees…Sorry
What’s the length of AC?
Or any of the angles?
Angles muthafucka! Angles!
Can’t solve. Need more info.
What does this have to do with general automotive? Fuzzy is correct the answer is 42
As for the Gen Auto thing, maybe he’s designing something custom for the Grand Am? We’ll give him time to explain…
not enought info… unless you want the answer as a variable
angles? fixed points? pivot points? what are the lenghts of each/every segment? The only force applied is uniformly along the length of AD?
EDIT: Angle A is 50 degrees. Yeah that would have helped. Sorry everyone. I feel like a db.
Length BC is Adjustable. Pivot points at A B and C. Length AC is unknown really but if you made it variable to give options that would be fine.
Fry…you are correct. I am looking to install some struts under my hood (ie. Adios Senior Prop Rod). I could just buy a “AutoZone” equivalent that would work but where is the fun in that?
To make the math easier we’ll make ABC a 6-8-12 right triangle.
The verticle Force at the centroid of the beam is 40 pounds.
Fsin(50)=40
F=25.7=perpendicular Force at the centroid.
So that makes torque at A = 25.7 * 20 = 514 in-lbs
Perpendicular force at C = 514/12 = 43 pounds
43/cos(50) = 62.5 pounds
Maybe. I haven’t done statics in probably 5 years. Might have made a mistake. A vertical load on BC of 62.5 pounds seems reasonable though. :shrug:
I just want to know if Fuzzy was right.
Because if he wasn’t then why did jrod jump in to verify it?
I think jrod forgot a question mark.
Fuzzy is correct with 42
I really can’t disagree because I too haven’t done this in like 4 years.
Thanks for working this out for me.
It is always the answer, it’s the answer to everything you know and see.
