That’s not correct.
Its (5/56)(4/55)(3/54)(2/53)(1/52)*(1/46)= 5.69114597e−9
Then 1/ 5.69114597e−9= 175711536
So, 1 in 175,711,536
Since americans have spent 1.5 billion on tickets, having all the combinations is easily covered.
That’s not correct.
Its (5/56)(4/55)(3/54)(2/53)(1/52)*(1/46)= 5.69114597e−9
Then 1/ 5.69114597e−9= 175711536
So, 1 in 175,711,536
Since americans have spent 1.5 billion on tickets, having all the combinations is easily covered.