can someone help me solve this

http://www.glenbrook.k12.il.us/GBSSCI/PHYS/Class/1DKin/U1L6a1.gif
A.) As per the first equation and the word problem, your initial velocity is 12 m/s, and the acceleration due to the gravitational pull of the moon is -1.6m/s/s. (1/2at^2… 1/2 * 1.6 * t^2… 0.8t^2)

B.) Check the equation in the lower left. Vf = Vi + at… 0 = 12 + -1.6t… t=7.5s

C.) Check the lower right equation. d=(Vi + Vf)/2 t… d=(12+0)/27.5=45m

D.) it took 7.5 seconds to go up. It’ll take 7.5 seconds to come back down. 15 seconds.

Amirite? :headbang: