How big is a big olive; a big Brazil nut?

A big olive (m = 0.087 kg) lies at the origin of an xy coordinate system, and a big Brazil nut (M = 0.58 kg) lies at the point (1.4, 3.0) m. At t = 0, a force o = (2 + 1) N begins to act on the olive, and a force n = (-2 -1) N begins to act on the nut. What is the (a)x and (b)y displacement of the center of mass of the olive-nut system at t = 7.4 s, with respect to its position at t = 0?

When not speaking to a physicist?

I don’t…know…

ow…My brain.

42?

exactly

After 7.4 seconds the olive is at (629.7+314.9) and the nut is at (-94.5-47.1)

The system’s center of mass is at (0,0)

:gotme: I can’t sleep and I like physics.

Realistically if they moved like that wouldn’t they collide?

Nope, their accelerations are the same magnitude so their paths are parallel, but the brazil nut never passes through the origin.