You can find an average of the negative forces by decelerating. Take your car up to say 100mph, then at a set point let off the gas and let it cost to a stop. Time it, and take the distance it took you to stop. That will give you the average force needed to overcome to get to 100 mph approx.
F=MA
Mass= your car
Acceleration will be the Distance/Time
This force will include your rolling friction, air friction etc.
It will not incluse power train loss.
Fry
March 14, 2008, 9:42am
22
ultradriver10000:
You can find an average of the negative forces by decelerating. Take your car up to say 100mph, then at a set point let off the gas and let it cost to a stop. Time it, and take the distance it took you to stop. That will give you the average force needed to overcome to get to 100 mph approx.
F=MA
Mass= your car
Acceleration will be the Distance/Time
This force will include your rolling friction, air friction etc.
It will not incluse power train loss.
There’s an interesting idea. Acceleration is usually delta-v over delta-t, but other than that little brainfart I like it.
Your correct, my distance and time was meant to be the change in distance / the change in time.
The distance being from the point of let off to the spot of actual stoppage.
The time would be from the same two points.
My balls can give better dyno numbers than a gtech
Fry
March 14, 2008, 12:31pm
25
Which still gives you velocity, not acceleration.
acceleration is the change in distance over the change in time square.
walter
March 14, 2008, 2:49pm
27
this thread is heavy with :picard:
squid
March 14, 2008, 3:18pm
28
Why not 4wd at Kennedy’s?
Guys, I’m not looking to actually do it… I was just wondering what the link to the site was…I thought it was much simpler.
squid
March 14, 2008, 3:40pm
30
Not even dying is simple any more.
Fry:
Only taking into account acceleration and drag:
F=m((v2-v1)/t) + .5rho v^2A Cd
Good luck getting any sort of accuracy out of it.
Well, that just gives you average force and at this point I’ve lost interest.
I prefer the time-dependent Schrodinger.
yah square the time my bad